Appendix
1.1 Proof of Theorem 3.1
Proof
Let \({\varvec{\delta }}\) and \(r\in \{1,\ldots ,q\}\) be arbitrary but fixed, and let \(\varvec{e}^{r}\) be the rth unit vector in \(\mathbb {R}^{q}\). Then,
$$\begin{aligned} \frac{\partial \bar{\varvec{x}}(s)}{\partial \theta _{r}}=\lim _{\xi \rightarrow 0}\frac{{\bar{\varvec{x}}} (s|{\varvec{\delta }},\varvec{\theta }^{\xi })-{\bar{\varvec{x}}}(s|{\varvec{\delta }},{\varvec{\theta }})}{\xi }, \end{aligned}$$
(41)
where \(\varvec{\theta }^{\xi }=\varvec{\theta }+\xi \varvec{e}^{r}\), \(s_{\text {delay}}^{\xi }\) and \(t_{\text {delay}}^{\xi }\) are the corresponding delayed time points in the new time horizon and the original time horizon such that
$$\begin{aligned} \mu \left( s_{\text {delay}}^{\xi }|{\varvec{\theta }}^{\xi }\right) =t_{\text {delay}}^{\xi } = \mu (s|{\varvec{\theta }}^{\xi })-h, \quad s\in [0,q]. \end{aligned}$$
Now, we will prove the theorem in the following steps.
Step 1: Preliminaries
For each real number \(\xi \in \mathbb {R}\), let \({\bar{\varvec{x}}}^{\xi }\) denote the function \({\bar{\varvec{x}}}\big (\cdot |\varvec{\delta },\varvec{\theta }^{\xi }\big )\). Then, it follows from (20) that, for each \(\xi \in \mathbb {R}\),
$$\begin{aligned} {\bar{\varvec{x}}}^{\xi }(s) = {\bar{\varvec{x}}}(s)+ \displaystyle \int _{0}^{s} \varvec{F}^{\xi }(t)\hbox {d}t,\quad s\in [0,q], \end{aligned}$$
(42)
where \({\bar{\varvec{x}}}(s)\) denotes the function \({\bar{\varvec{x}}}\big (\cdot |\varvec{\delta },\varvec{\theta }\big )\), and \(\varvec{F}^{\xi } \) is defined as follows:
$$\begin{aligned} \varvec{F}^{\xi }(s):=\left\{ \begin{array}{l@{\quad }r} \theta _{\lfloor s\rfloor +1}^{\xi } \varvec{f}\big ( {\bar{\varvec{x}}}(s|\varvec{\delta },\varvec{\theta }^{\xi }), {\bar{\varvec{x}}}\left( s_{\text {delay}}^{\xi }|\varvec{\delta },\varvec{\theta }^{\xi }\right) ,{\varvec{\delta }} \big ), &{}\text {if }s_{\text {delay}}\ge 0,\\ \\ \theta _{\lfloor s\rfloor +1}^{\xi } \varvec{f}\big ({\bar{\varvec{x}}}(s|\varvec{\delta },\varvec{\theta }^{\xi }), {\bar{\varvec{x}}}\left( s_{\text {delay}}^{\xi }|\varvec{\delta },\varvec{\theta }^{\xi }\right) ,{\varvec{\delta }}, \varphi \left( t_{\text {delay}}^{\xi }\right) \big ),&{}\text {if }s_{\text {delay}}<0. \end{array}\right. \end{aligned}$$
Define
$$\begin{aligned} \varGamma ^{\xi }(s)= & {} {\bar{\varvec{x}}}(s|{\varvec{\delta }},\varvec{\theta }^{\xi })-{\bar{\varvec{x}}}(s|{\varvec{\delta }},{\varvec{\theta }})\nonumber \\= & {} \displaystyle \int _{0}^{s}\big (\varvec{F}^{\xi }- \varvec{F}^{0}\big )\hbox {d}t. \end{aligned}$$
(43)
Applying the mean value theorem, we have, for \(s\in [0,q]\),
$$\begin{aligned} \displaystyle \varvec{F}^{\xi }(s)- \varvec{F}^{0}(s)= & {} \displaystyle \int _{0}^{1}\bigg \{ \displaystyle \frac{\partial \varvec{f}\big (\bar{\varvec{x}}+\eta \varGamma ^{\xi }(s),{\bar{\varvec{x}}}_{d}+\eta ({\bar{\varvec{x}}}_{d}^{\xi }-{\bar{\varvec{x}}}_{d}),{\varvec{\theta }}+\eta \xi \varvec{e}^{r},{\varvec{\delta }}\big )}{\partial {\bar{\varvec{x}}}}\varGamma ^{\xi }(s)\nonumber \\&+\, \displaystyle \frac{\partial \varvec{f}\big (\bar{\varvec{x}}+\eta \varGamma ^{\xi }(s),{\bar{\varvec{x}}}_{d}+\eta ({\bar{\varvec{x}}}_{d}^{\xi }-{\bar{\varvec{x}}}_{d}),{\varvec{\theta }}+\eta \xi \varvec{e}^{r},{\varvec{\delta }}\big )}{\partial {\bar{\varvec{x}}}_{d}}({\bar{\varvec{x}}}_{d}^{\xi }-{\bar{\varvec{x}}}_{d})\nonumber \\&+\,\displaystyle \frac{\partial \varvec{f}\big (\bar{\varvec{x}}+\eta \varGamma ^{\xi }(s),{\bar{\varvec{x}}}_{d}+\eta ({\bar{\varvec{x}}}_{d}^{\xi }-{\bar{\varvec{x}}}_{d}),{\varvec{\theta }}+\eta \xi \varvec{e}^{r},{\varvec{\delta }}\big )}{\partial \theta _{r}}\xi \bigg \}\hbox {d}\eta , \end{aligned}$$
(44)
and
$$\begin{aligned} {\bar{\varvec{x}}}_{d}^{\xi }-{\bar{\varvec{x}}}_{d}^{0}= & {} {\bar{\varvec{x}}}\left( s_{\text {delay}}^{\xi }|\varvec{\delta },\varvec{\theta }^{\xi }\right) -{\bar{\varvec{x}}}\left( s_{\text {delay}}|\varvec{\delta },\varvec{\theta }\right) \\= & {} {\bar{\varvec{x}}}\left( s_{\text {delay}}^{\xi }|\varvec{\delta },\varvec{\theta }^{\xi }\right) -{\bar{\varvec{x}}}\left( s_{\text {delay}}|\varvec{\delta },\varvec{\theta }^{\xi }\right) +{\bar{\varvec{x}}}\left( s_{\text {delay}}|\varvec{\delta },\varvec{\theta }^{\xi }\right) -{\bar{\varvec{x}}}\left( s_{\text {delay}}|\varvec{\delta },\varvec{\theta }\right) \\= & {} {\bar{\varvec{x}}}\left( s_{\text {delay}}^{\xi }|\varvec{\delta },\varvec{\theta }^{\xi }\right) -{\bar{\varvec{x}}}\left( s_{\text {delay}}|\varvec{\delta },\varvec{\theta }^{\xi }\right) +\varGamma ^{\xi }(s_{\text {delay}}) \end{aligned}$$
From Assumption \(\mathbf A1 \), it follows that the state set \(\{{\bar{\varvec{x}}}^{\xi }(s): \xi \in [-a,a]\}\) is equibounded on [0, q], where \(a>0\) is a fixed small real number. Hence, there exists a real number \(C_{1}>0\) such that for each \(\xi \in [-a,a]\),
$$\begin{aligned} {\bar{\varvec{x}}}^{\xi }(s)\in \mathcal {N}_{n}(C_{1}), \quad s\in [0,q], \end{aligned}$$
where \(\mathcal {N}_{n}(C_{1})\) denotes the closed ball in \(\mathbb {R}^{n}\) of radius \(C_{1}\) centered at the origin. Note that, \(\mathcal {N}_{n}(C_{1})\) is convex, thus, for each \(\xi \in [-a,a]\),
$$\begin{aligned} {\bar{\varvec{x}}}(s)+\eta \varGamma ^\xi (s)\in \mathcal {N}_{n}(C_{1}),\quad s\in [0,q],~\eta \in [0,1]. \end{aligned}$$
Furthermore, it is easy to see that for each \(\xi \in [-a,a]\),
$$\begin{aligned} \varvec{\theta }+\eta \xi \varvec{e}^{r}\in \mathcal {N}_{q}(C_{2}),\quad \eta \in [0,1], \end{aligned}$$
where \(C_{2} :=|\varvec{\theta }|_{q}+a. \) Recall from Assumption \(\mathbf A2 \) that \(\partial \varvec{f}/\partial \varvec{x}\) and \(\partial \varvec{f}/\partial \theta _{r}\) are continuous. Hence, it follows from the compactness of [0, T], \(\mathcal {V}\), \(\mathcal {N}_{n}(C_{1})\) and \(\mathcal {N}_{q}(C_{2})\) and the definitions of \(z(s|\varvec{\theta })\) and \(\phi \) that there exists a real number \(C_{3}>0\) such that, for each \(\xi \in [-a,a]\),
$$\begin{aligned} \bigg |\frac{\partial \varvec{f}^{\xi }_{\eta }}{\partial {\bar{\varvec{x}}}}\bigg |_{n\times n}\le & {} C_{3},\quad s\in [0,q],~\eta \in [0,1],\\ \bigg |\frac{\partial \varvec{f}^{\xi }_{\eta }}{\partial {\bar{\varvec{x}}}_{d}}\bigg |_{n\times n}\le & {} C_{3},\quad s\in [0,q],~\eta \in [0,1],\\ \bigg |\frac{\partial \varvec{f}^{\xi }_{\eta }}{\partial \theta _{r}}\bigg |_{n}\le & {} C_{3},\quad s\in [0,q],~\eta \in [0,1],\\ \bigg |\frac{\partial \phi _{\eta }^{\xi }}{\partial t}\bigg |_{n}\le & {} C_{3},\quad s\in [0,q],~\eta \in [0,1],\\ \end{aligned}$$
where \(\varvec{f}^{\xi }_{\eta }\) denotes \(\varvec{f}\big (\bar{\varvec{x}}+\eta \varGamma ^{\xi }(t),{\bar{\varvec{x}}}_{d}+\eta ({\bar{\varvec{x}}}_{d}^{\xi }-{\bar{\varvec{x}}}_{d}),{\varvec{\theta }}+\eta \xi \varvec{e}^{r},{\varvec{\delta }}\big )\), and \(\phi _{\eta }^{\xi }\) denotes \(\phi (\mu (t|\varvec{\theta }+\eta \xi \varvec{e}^{r})-h)\), and \(| \cdot |\) denotes the Euclidian norm.
Step 2: The function
\(\varGamma ^{\xi }(s)\)
is of order
\(\xi \)
Let \(\xi \in [-a,a]\) be arbitrary. When \(s_{\text {delay}}<0\), taking the norm of both sides of (43) and applying the definition of \(C_{3}\) gives
$$\begin{aligned} |\varGamma ^{\xi }(s)|_{n} = \bigg |\int _{0}^{s}\int _{0}^{1}\bigg \{\frac{\partial \varvec{f}^{\xi }_{\eta }}{\partial {\bar{\varvec{x}}}}\varGamma ^{\xi }(t)+ \frac{\partial \varvec{f}^{\xi }_{\eta }}{\partial \theta _{r}}\xi +\frac{\partial \varvec{f}^{\xi }_{\eta }}{\partial {\bar{\varvec{x}}}_{d}}\left( \phi ^{\xi }_{\eta }-\phi ^{0}_{\eta }\right) \bigg \}\hbox {d}\eta \hbox {d}t\bigg |_{n}, \end{aligned}$$
(45)
where
$$\begin{aligned} \phi ^{\xi }_{\eta }-\phi ^{0}_{\eta }= & {} \phi (\mu (t|\varvec{\theta }+\xi \varvec{e}^{r})-h) -\phi (\mu (t|\varvec{\theta })-h)\\= & {} \xi \frac{\partial \phi (\mu (t|\varvec{\theta }+\eta \xi \varvec{e}^{r})-h)}{\partial t}\frac{\partial \mu (t|\varvec{\theta }+\eta \xi \varvec{e}^{r})}{\partial \theta _{r}}, \quad \eta \in [0,1]. \end{aligned}$$
Thus, we have
$$\begin{aligned} |\varGamma ^{\xi }(s)|_{n}\le C_{3}|\xi |+C_{3}^{2}T|\xi |+\int _{0}^{s}C_{3}|\varGamma ^{\xi }(t)|_{n}\hbox {d}t, \quad s_{\text {delay}}<0. \end{aligned}$$
(46)
Applying Gronwall’s Lemma gives
$$\begin{aligned} |\varGamma ^{\xi }(s)|_{n}\le \left( C_{3}+C_{3}^{2}T\right) \exp {(C_{3}q)}|\xi |, \quad s\in [0,P_{1}[. \end{aligned}$$
(47)
When \(s_{\text {delay}}\ge 0\),
where \(P_{1}\) is a time point in the new time horizon such that
$$\begin{aligned} \mu (P_{1}|\varvec{\theta })=h. \end{aligned}$$
Since \(s_{\text {delay}}\ge 0\), it follows from the definition of \(s_{\text {delay}}\) that
$$\begin{aligned} \bigg |\int _{P_{1}}^{s}\int _{0}^{1}\frac{ \partial \varvec{f}^{\xi }_{\eta }}{\partial {\bar{\varvec{x}}}_{d}}\varGamma ^{\xi }(s_{\text {delay}}) \hbox {d}\eta \hbox {d}t \bigg |_{n} \le \int _{P_{1}}^{s}C_{3}|\varGamma ^{\xi }(s_{\text {delay}})|_{n}\hbox {d}t\le \int _{0}^{s}C_{3}|\varGamma ^{\xi }(t)|_{n}\hbox {d}t, \end{aligned}$$
and by the mean value theorem
$$\begin{aligned}&\displaystyle \bigg |\int _{P_{1}}^{s}\int _{0}^{1}\frac{ \partial \varvec{f}^{\xi }_{\eta }}{\partial {\bar{\varvec{x}}}_{z}}\big [\bar{\varvec{x}}(s_{\text {delay}}^{\xi }|\varvec{\delta },\varvec{\theta }^{\xi })-\bar{\varvec{x}}(s_{\text {delay}}|\varvec{\delta },\varvec{\theta }^{\xi })\big ] \hbox {d}\eta \hbox {d}t \bigg |_{n}\nonumber \\&\quad \le \displaystyle C_{3}\int _{P_{1}}^{s}\int _{0}^{1}\bigg |\frac{\partial {\bar{\varvec{x}}}(z(t,\varvec{\theta }+\iota \xi \varvec{e}^{r})|\varvec{\delta },\varvec{\theta }+\iota \xi \varvec{e}^{r})}{\partial z}\frac{\partial z}{\partial \theta _{r}}\xi \bigg |_{n}\hbox {d}\iota \hbox {d}t \le C_{3}^{3}q|\xi |, \end{aligned}$$
(48)
where \(\iota \in [0,1].\) Again, by applying Gronwall’s Lemma, we have
$$\begin{aligned} |\varGamma ^{\xi }(s)|_{n}\le & {} \left( C_{3}+C_{3}^{2}T\right) \exp {(C_{3}q)}|\xi |+C_{3}|\xi | +C_{3}^{3}q|\xi |+\int _{0}^{s}2C_{3}|\varGamma ^{\xi }(t)|_{n}\hbox {d}t\nonumber \\\le & {} \left( C_{3}+C_{3}^{2}T\right) \exp {(C_{3}q)}|\xi | +\left( C_{3}+C_{3}^{3}q\right) \exp {(2C_{3}q)}|\xi |. \end{aligned}$$
(49)
Since \(\xi \in [-a,a]\) is arbitrary, the function \(\varGamma ^{\xi }(s)\) is of order \(\xi \).
Step 3: The definition of
\(\rho \)
and its properties
For each \(\xi \in \mathbb {R}\), define the corresponding functions \(\lambda ^{1,\xi }{:}\,[0,q]\rightarrow \mathbb {R}^{n},\)
\(\lambda ^{2,\xi }{:}\,[0,q]\rightarrow \mathbb {R}^{n}\) and \(\lambda ^{3,\xi }{:}\,[0,q]\rightarrow \mathbb {R}^{n}\) as follows:
$$\begin{aligned} \lambda ^{1,\xi }(t):= & {} \int _{0}^{1}\bigg \{\frac{\partial \varvec{f}\big (\bar{\varvec{x}}+\eta \varGamma ^{\xi }(t),{\bar{\varvec{x}}}_{d} +\eta ({\bar{\varvec{x}}}_{d}^{\xi }-{\bar{\varvec{x}}}_{d}),{\varvec{\theta }} +\eta \xi \varvec{e}^{r},{\varvec{\delta }}\big )}{\partial {\bar{\varvec{x}}}}\nonumber \\&\qquad \qquad -\,\frac{\partial \varvec{f}\big (\bar{\varvec{x}},{\bar{\varvec{x}}}_{d},{\varvec{\theta }},{\varvec{\delta }}\big )}{\partial {\bar{\varvec{x}}}} \bigg \}\varGamma ^{\xi }(t)\hbox {d}\eta \end{aligned}$$
(50)
$$\begin{aligned} \lambda ^{2,\xi }(t):= & {} \int _{0}^{1}\bigg \{\frac{\partial \varvec{f}\big (\bar{\varvec{x}}+\eta \varGamma ^{\xi }(t),{\bar{\varvec{x}}}_{d} +\eta ({\bar{\varvec{x}}}_{d}^{\xi }-{\bar{\varvec{x}}}_{d}),{\varvec{\theta }}+\eta \xi \varvec{e}^{r}, {\varvec{\delta }}\big )}{\partial {\bar{\varvec{x}}}_{d}}\nonumber \\&\qquad \qquad -\,\frac{\partial \varvec{f}\big (\bar{\varvec{x}},{\bar{\varvec{x}}}_{d},{\varvec{\theta }},{\varvec{\delta }}\big )}{\partial {\bar{\varvec{x}}}_{d}} \bigg \}({\bar{\varvec{x}}}_{d}^{\xi }-{\bar{\varvec{x}}}_{d})\hbox {d}\eta \end{aligned}$$
(51)
$$\begin{aligned} \lambda ^{3,\xi }(t):= & {} \int _{0}^{1}\bigg \{\frac{\partial \varvec{f}\big (\bar{\varvec{x}}+\eta \varGamma ^{\xi }(t), {\bar{\varvec{x}}}_{d}+\eta ({\bar{\varvec{x}}}_{d}^{\xi }-{\bar{\varvec{x}}}_{d}), {\varvec{\theta }}+\eta \xi \varvec{e}^{r},{\varvec{\delta }}\big )}{\partial \theta _{r}}\nonumber \\&\qquad \qquad -\,\frac{\partial \varvec{f}\big (\bar{\varvec{x}},{\bar{\varvec{x}}}_{d},{\varvec{\theta }},{\varvec{\delta }}\big )}{\partial \theta _{r}} \bigg \}\xi \hbox {d}\eta \end{aligned}$$
(52)
In addition, let the function \(\rho {:}\,[-a,0[\cup ]0,a]\rightarrow \mathbb {R}\) be defined as follows:
$$\begin{aligned} \rho (\xi ):=|\xi |^{-1}\int _{0}^{q}\{|\lambda ^{1,\xi }(t)|_{n} +|\lambda ^{2,\xi }(t)|_{n}+|\lambda ^{3,\xi }(t)|_{n}\}\hbox {d}t \end{aligned}$$
(53)
Since the function \(\varGamma ^{\xi }(s)\) is of order \(\xi \), it follows that
$$\begin{aligned}&{\bar{\varvec{x}}} +\eta \varGamma ^{\xi }(t)\rightarrow {\bar{\varvec{x}}} ,\quad \text {as}~ \xi \rightarrow 0, \end{aligned}$$
(54)
$$\begin{aligned}&{\bar{\varvec{x}}}_{d}+\eta \left( {\bar{\varvec{x}}}_{d}^{\xi }-{\bar{\varvec{x}}}_{d}\right) \rightarrow {\bar{\varvec{x}}}_{d} ,\quad \text {as}~ \xi \rightarrow 0, \end{aligned}$$
(55)
uniformly with respective to \(t\in [0,q]\) and \(\eta \in [0,1]\). Meanwhile, it is obvious that
$$\begin{aligned} \varvec{\theta }+\eta \xi \varvec{e}^{r}\rightarrow \varvec{\theta }, \quad \text {as}~ \xi \rightarrow 0, \end{aligned}$$
(56)
uniformly with respect to \(\eta \in [0,1]\). Since the convergences in (54) and (55) take place inside the ball \(\mathcal {N}_{n}(C_{1})\), the convergence in (56) takes place inside of the ball \(\mathcal {N}_{n}(C_{2})\), \(\partial \varvec{f}/\partial {\bar{\varvec{x}}}\), \(\partial \varvec{f}/\partial {\bar{\varvec{x}}}_{z}\) and \(\partial \varvec{f}/\partial \theta _{r}\) are uniformly continuous on the compact set \([0,q]\times \mathcal {N}_{n}(C_{1})\times \mathcal {N}_{n}(C_{1})\times \mathcal {V}\times \mathcal {N}_{n}(C_{2})\),
$$\begin{aligned} \frac{\partial \varvec{f}\big (\bar{\varvec{x}}^{0}+\eta \varGamma ^{\xi }(s),{\bar{\varvec{x}}}_{d} +\eta ({\bar{\varvec{x}}}_{d}^{\xi }-{\bar{\varvec{x}}}_{d}),{\varvec{\theta }}+\eta \xi \varvec{e}^{r}, {\varvec{\delta }}\big )}{\partial {\bar{\varvec{x}}}}\rightarrow & {} \frac{\partial \varvec{f}\big (\bar{\varvec{x}}^{0},{\bar{\varvec{x}}}_{d},{\varvec{\theta }},{\varvec{\delta }}\big )}{\partial {\bar{\varvec{x}}}},\quad \text {as}~\xi \rightarrow 0,\\ \frac{\partial \varvec{f}\big (\bar{\varvec{x}}^{0}+\eta \varGamma ^{\xi }(s),{\bar{\varvec{x}}}_{d}+\eta ({\bar{\varvec{x}}}_{d}^{\xi }-{\bar{\varvec{x}}}_{d}),{\varvec{\theta }}+\eta \xi \varvec{e}^{r},{\varvec{\delta }}\big )}{\partial {\bar{\varvec{x}}}_{d}}\rightarrow & {} \frac{\partial \varvec{f}\big (\bar{\varvec{x}}^{0},{\bar{\varvec{x}}}_{d},{\varvec{\theta }},{\varvec{\delta }}\big )}{\partial {\bar{\varvec{x}}}_{d}},\quad \text {as}~\xi \rightarrow 0,\\ \frac{\partial \varvec{f}\big (\bar{\varvec{x}}^{0}+\eta \varGamma ^{\xi }(s),{\bar{\varvec{x}}}_{d}+\eta ({\bar{\varvec{x}}}_{d}^{\xi }-{\bar{\varvec{x}}}_{d}),{\varvec{\theta }}+\eta \xi \varvec{e}^{r},{\varvec{\delta }}\big )}{\partial \theta _{r}}\rightarrow & {} \frac{\partial \varvec{f}\big (\bar{\varvec{x}}^{0},{\bar{\varvec{x}}}_{d},{\varvec{\theta }},{\varvec{\delta }}\big )}{\partial \theta _{r}},\quad \text {as}~\xi \rightarrow 0,\\ \frac{\partial {\bar{\varvec{x}}}\left( s_{\text {delay}}^{\xi ,\iota }|\varvec{\delta },\varvec{\theta }+\iota \xi \varvec{e}^{r}\right) }{\partial s_{\text {delay}}}\rightarrow & {} \frac{\partial {\bar{\varvec{x}}}\left( s_{\text {delay}}|\varvec{\delta },\varvec{\theta }\right) }{\partial s_{\text {delay}}},\quad \text {as}~\xi \rightarrow 0,\\ \frac{\partial s_{\text {delay}}^{\xi ,\iota }}{\partial \theta _{r}}\rightarrow & {} \frac{\partial s_{\text {delay}}}{\partial \theta _{r}},\quad \text {as}~\xi \rightarrow 0, \end{aligned}$$
uniformly with respect to \(t\in [0,q]\), \(\eta \in [0,1]\) and \(\iota \in [0,1]\), where \(s_{\text {delay}}^{\xi ,\iota }\) is the corresponding delayed time of the control \(\varvec{\theta }+\iota \xi \varvec{e}^{r}\). These results together with (49) indicate that \(|\xi |^{-1}\lambda ^{1,\xi }\rightarrow \varvec{0}\), \(|\xi |^{-1}\lambda ^{2,\xi }\rightarrow \varvec{0}\) and \(|\xi |^{-1}\lambda ^{3,\xi }\rightarrow \varvec{0}\) uniformly on [0, q] as \(\xi \rightarrow 0\). Thus,
$$\begin{aligned} \lim _{\xi \rightarrow 0}\rho (\xi )=\varvec{0}. \end{aligned}$$
(57)
Step 4: The final step
Let \(\xi \in [-a,0[\cup ]0,a]\) be arbitrary but fixed. Then, it follows from (43) that
$$\begin{aligned} \varGamma ^{\xi }(s)= & {} \int _{0}^{s}\big [\lambda ^{1,\xi }(t)+\lambda ^{2,\xi }(t)+\lambda ^{3,\xi }(t)\big ]\hbox {d}t+\int _{0}^{s}\frac{\partial \varvec{f}\big (\bar{\varvec{x}} ,{\bar{\varvec{x}}}_{d},{\varvec{\theta }},{\varvec{\delta }}\big )}{\partial {\bar{\varvec{x}}}}\varGamma ^{\xi }(t)\hbox {d}t\nonumber \\&+\int _{0}^{s}\frac{\partial \varvec{f}\big (\bar{\varvec{x}} ,{\bar{\varvec{x}}}_{d},{\varvec{\theta }},{\varvec{\delta }}\big )}{\partial {\bar{\varvec{x}}}_{d}}\left[ \varGamma ^{\xi }(s_{\text {delay}}+\frac{\partial {\bar{\varvec{x}}}(s_{\text {delay}}^{\xi ,\iota }|(\varvec{\delta },\varvec{\theta }+\iota \xi \varvec{e}^{r}))}{\partial s_{\text {delay}}}\frac{\partial s_{\text {delay}}^{\xi ,\iota }}{\partial \theta _{r}}\xi \right] \hbox {d}t\nonumber \\&+\int _{0}^{s}\frac{\partial \varvec{f}\big (\bar{\varvec{x}} ,{\bar{\varvec{x}}}_{d},{\varvec{\theta }},{\varvec{\delta }}\big )}{\partial \theta _{r}}\xi \hbox {d}t \end{aligned}$$
(58)
Furthermore, integrating the auxiliary system gives
$$\begin{aligned} \varLambda ^{r}(s|\varvec{\delta ,\theta })= & {} \int _{0}^{s}\frac{\partial \varvec{f}\big (\bar{\varvec{x}} ,{\bar{\varvec{x}}}_{d},{\varvec{\theta }},{\varvec{\delta }}\big )}{\partial {\bar{\varvec{x}}}}\varLambda ^{r}(t|\varvec{\delta ,\theta })\hbox {d}t\nonumber \\&+\int _{0}^{s}\frac{\partial \varvec{f}\big (\bar{\varvec{x}} ,{\bar{\varvec{x}}}_{d},{\varvec{\theta }},{\varvec{\delta }}\big )}{\partial {\bar{\varvec{x}}}_{d}}\left[ \varLambda ^{r}(s_{\text {delay}}|\varvec{\delta ,\theta })+\frac{\partial {\bar{\varvec{x}}}(s_{\text {delay}}|(\varvec{\delta },\varvec{\theta }))}{\partial s_{\text {delay}}}\frac{\partial s_{\text {delay}}}{\partial \theta _{r}}\right] \hbox {d}t\nonumber \\&+\int _{0}^{s}\frac{\partial \varvec{f}\big (\bar{\varvec{x}} ,{\bar{\varvec{x}}}_{d},{\varvec{\theta }},{\varvec{\delta }}\big )}{\partial \theta _{r}}\hbox {d}t \end{aligned}$$
(59)
Multiplying (58) by \(\xi ^{-1}\), and subtracting it from (59) yields
$$\begin{aligned}&\xi ^{-1}\varGamma ^{\xi }(s)-\varLambda ^{r}(s|\varvec{\delta ,\theta })\nonumber \\&\quad =\xi ^{-1}\int _{0}^{s}\big [\lambda ^{1,\xi }(t)+\lambda ^{2,\xi }(t)+\lambda ^{3,\xi }(t)\big ]\hbox {d}t\nonumber \\&\qquad +\int _{0}^{s}\frac{\partial \varvec{f}\big (\bar{\varvec{x}} ,{\bar{\varvec{x}}}_{d},{\varvec{\theta }},{\varvec{\delta }}\big )}{\partial {\bar{\varvec{x}}}}(\xi ^{-1}\varGamma ^{\xi }(t)-\varLambda ^{r}(s|\varvec{\delta ,\theta }))\hbox {d}t\nonumber \\&\qquad +\int _{0}^{s}\frac{\partial \varvec{f}\big (\bar{\varvec{x}} ,{\bar{\varvec{x}}}_{d},{\varvec{\theta }},{\varvec{\delta }}\big )}{\partial {\bar{\varvec{x}}}_{z}}\bigg [\left( \xi ^{-1}\varGamma ^{\xi }(s_{\text {delay}})-\varLambda ^{r}(s_{\text {delay}}|\varvec{\delta ,\theta })\right) \nonumber \\&\qquad +\,\frac{\partial {\bar{\varvec{x}}}\left( s_{\text {delay}}^{\xi ,\iota }|\left( \varvec{\delta },\varvec{\theta }+\iota \xi \varvec{e}^{r}\right) \right. }{\partial s_{\text {delay}}}\frac{\partial s_{\text {delay}}^{\xi ,\iota }}{\partial \theta _{r}}-\frac{\partial {\bar{\varvec{x}}}\left( s_{\text {delay}}|(\varvec{\delta },\varvec{\theta })\right) }{\partial s_{\text {delay}}}\frac{\partial s_{\text {delay}}}{\partial \theta _{r}}\bigg ]\hbox {d}t \end{aligned}$$
(60)
Let
$$\begin{aligned} \bar{\rho }(\xi )= & {} \rho (\xi )+\int _{0}^{s}C_{3}\bigg |\frac{\partial {\bar{\varvec{x}}}(s_{\text {delay}}^{\xi ,\iota }|(\varvec{\delta },\varvec{\theta }+\iota \xi \varvec{e}^{r})}{\partial s_{\text {delay}}}\frac{\partial s_{\text {delay}}^{\xi ,\iota }}{\partial \theta _{r}}\\&-\, \frac{\partial {\bar{\varvec{x}}}(s_{\text {delay}}|(\varvec{\delta },\varvec{\theta }))}{\partial s_{\text {delay}}}\frac{\partial s_{\text {delay}}}{\partial \theta _{r}}\bigg |_{n}\hbox {d}t. \end{aligned}$$
Then, it is easy to see that \(\rho ^{\prime }(\xi )\rightarrow 0,\) as \(\xi \rightarrow 0\). Therefore,
$$\begin{aligned}&|\xi ^{-1}\varGamma ^{\xi }(s)-\varLambda ^{r}(s|\varvec{\delta ,\theta })|_{n}\\&\quad \le \rho (\xi )+\int _{0}^{s}C_{3}|\xi ^{-1}\varGamma ^{\xi }(t)-\varLambda ^{r}(t|\varvec{\delta ,\theta })|_{n}\hbox {d}t\\&\qquad +\int _{0}^{s}C_{3}|\xi ^{-1}\varGamma ^{\xi }(s_{\text {delay}})-\varLambda ^{r}(s_{\text {delay}}|\varvec{\delta ,\theta })|_{n}\hbox {d}t\\&\qquad +\int _{0}^{s}C_{3}\bigg |\frac{\partial {\bar{\varvec{x}}}(s_{\text {delay}}^{\xi ,\iota }|(\varvec{\delta },\varvec{\theta }+\iota \xi \varvec{e}^{r})}{\partial s_{\text {delay}}}\frac{\partial s_{\text {delay}}^{\xi ,\iota }}{\partial \theta _{r}}-\frac{\partial {\bar{\varvec{x}}}(s_{\text {delay}}|(\varvec{\delta },\varvec{\theta }))}{\partial s_{\text {delay}}}\frac{\partial s_{\text {delay}}}{\partial \theta _{r}}\bigg |_{n}\hbox {d}t\\&\quad \le \bar{\rho }(\xi )+\int _{0}^{s}2C_{3}|\xi ^{-1}\varGamma ^{\xi }(t) -\varLambda ^{r}(t|\varvec{\delta ,\theta })|_{n}\hbox {d}t \end{aligned}$$
By Gronwall’s Lemma
$$\begin{aligned} |\xi ^{-1}\varGamma ^{\xi }(s)-\varLambda ^{r}(s|\varvec{\delta ,\theta })|_{n} \le \bar{\rho }(\xi )\exp {(2C_{3}q)},\quad s\in [0,q]. \end{aligned}$$
(61)
Noting that \(\xi \in [-a,0[\cup ]0,a]\) is arbitrary, we can take the limit as \(\xi \rightarrow 0\) in (61) and then apply (57) to get
$$\begin{aligned} \lim _{\xi \rightarrow 0}\xi ^{-1}\varGamma ^{\xi }(s)=\varLambda ^{r}(s|\varvec{\delta },\varvec{\theta }), \quad s\in [0,q]. \end{aligned}$$
\(\square \)