On the expected discounted penalty function at ruin of a surplus process with interest

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Abstract

In this paper, we study the expected value of a discounted penalty function at ruin of the classical surplus process modified by the inclusion of interest on the surplus. The ‘penalty’ is simply a function of the surplus immediately prior to ruin and the deficit at ruin. An integral equation for the expected value is derived, while the exact solution is given when the initial surplus is zero. Dickson’s [Insurance: Mathematics and Economics 11 (1992) 191] formulae for the distribution of the surplus immediately prior to ruin in the classical surplus process are generalised to our modified surplus process.

Introduction

Consider a compound Poisson risk model. Assume that Tn=∑k=1nYk is the time of the nth claim and Xn is the amount of the nth claim. Suppose that {Xn,n≥1} and {Yn,n≥1} are two independent sequences of i.i.d. positive random variables, where {Xn,n≥1} have common distribution F(x)=Pr{X1x} with mean μ>0, and {Yn,n≥1} have common exponential distribution Pr{Y1x}=1−exp{−λx}, x≥0, where λ>0.

The number of claims up to time t is denoted by N(t)=sup{n:Tnt}. The claim number process is a Poisson process with rate λ, and the aggregate claim amount up to time t is Z(t)=∑n=1N(t)Xn.Assume that the insurer receives interest on its surplus at a constant force δ per unit time. Let Uδ(t) denote the surplus at time t. Then Uδ(t)=ueδt+cs̄(δ)−∫0teδ(t−x)dZ(x),where u is the initial surplus and c>λμ is the rate of premium income per unit time.

Let the time of ruin be Tδ=inf{t:Uδ(t)<0},ifUδ(t)≥0forallt>0.Denote by ψδ(u) the ruin probability for the surplus process given by Eq. (1.1). Then ψδ(u)=Pr{Tδ<∞}=Pr{∪t≥0(Uδ(t)<0)}.The following notation applies throughout this paper: f(x)=ddxF(x),F1(x)=1−F̄1(x)=1μ0xF̄(t)dt,ψ̄δ(u)=1−ψδ(u),ψ(u)=ψ0(u),ψ(0)=λμc,U(Tδ)=thesurplusimmediatelypriortoruin,|U(Tδ)|=thedeficitatruin,Fδ(u,x)=Pr{U(Tδ)≤x,Tδ<∞},fδ(u,x)=ddxFδ(u,x),Hδ(u,x,y)=Pr{U(Tδ)≤x,|U(Tδ)|≤y,Tδ<∞},hδ(u,x,y)=2∂x∂yHδ(u,x,y).We consider the expected value of a discounted function of the surplus immediately prior to ruin and the deficit at ruin when ruin occurs as a function of the initial surplus u, namely, Φδ,α(u)=E(w(U(Tδ),|U(Tδ)|)e−αTδI(Tδ<∞)),where I(A) is the indicator function of a set A, w is a non-negative function, and α is a non-negative valued parameter. We can interpret exp{−αTδ} as the ‘discounting factor’.

The function Φδ,α(u) provides a unified means of studying the joint distribution of the surplus immediately prior to ruin and the deficit at ruin. The distributions of these quantities, both joint and marginal, have been studied by many authors including Dickson, 1992, Dufresne and Gerber, 1988, Gerber et al., 1987, Gerber and Shiu, 1997, Gerber and Shiu, 1998 and Lin and Willmot (1999). In particular, Gerber and Shiu (1998) studied the function Φ0,α(u) in detail, but they did not consider the case when δ>0.

In this paper, we will follow ideas in Sundt and Teugels (1995). In particular, we will consider the function Φδ,0(u)=Φδ(u). We will also derive an integral equation for Φδ,α(u) and find the Laplace transform of an auxiliary function of Φδ,α(u). We then find an exact solution for Φδ(0) and generalise Dickson’s (1992) formulae for the distribution of the surplus prior to ruin when δ=0 to the situation when δ>0. Applications of the results will be illustrated by a variety of examples.

Section snippets

Integral equations

Using similar arguments to Gerber and Shiu (1998) and Sundt and Teugels (1995), we condition on the time, t, and on the amount, x, of the first claim. We note that if x≤ueδt+cs̄(δ), then ruin does not occur, but if x>ueδt+cs̄(δ), then ruin occurs. Thus, Φδ,α(u)=∫0λe−λt0E(w(U(Tδ),|U(Tδ)|)e−αTδI(Tδ<∞)|X1=x,Y1=t)dF(x)dt=∫0λe−(λ+α)t0ueδt+cs̄(δ)Φδ,α(ueδt+cs̄(δ)−x)dF(x)dt+∫0λe−(λ+α)tueδt+cs̄(δ)w(ueδt+cs̄(δ),x−ueδt−cs̄(δ))dF(x)dt.Substituting y=ueδt+cs̄(δ)=ueδt+c(eδt−1)/δ in the above

The exact solution for Φδ(0)

We define an auxiliary function of Φδ(u) as Zδ(u)=Φδ(0)−Φδ(u)Φδ(0).Then Zδ(0)=0. Also, if the claim size distribution F is sufficiently regular, then Φδ(u)→0 as u→∞. In this case, limu→∞Zδ(u)=1 and we can find the Laplace transform of Zδ, namely, γδ(s)=∫0e−sxdZδ(x),with γδ(0)=1. Therefore, we assume that Φδ(u)→0 as u→∞. In particular, a sufficient condition for this assumption is that w is bounded. As 1−ψ is a compound geometric distribution function, if F has a finite second moment, then 1−ψ

The distribution of the surplus prior to ruin

Throughout this section we assume that F is a continuous distribution with density f. From Eq. (3.14), we have hδ(0,x,y)=2∂y∂xHδ(0,x,y)=λκδf(x+y)∫0exp−(c+δx)z+λμ∫0zφ1(δs)dsdz,and Fδ(0,x)=limy→∞Hδ(0,x,y)=λκδ00xe−δszF̄(s)dsexp−cz+λμ∫0zφ1(δs)dsdz,which gives fδ(0,x)=ddxFδ(0,x)=λκδF̄(x)∫0exp−(c+δx)z+λμ∫0zφ1(δs)dsdz.Thus, , yield hδ(0,x,y)=f(x+y)F̄(x)fδ(0,x).Eq. (4.3) is a special case of a more general result, namely, hδ(u,x,y)=f(x+y)F̄(x)fδ(u,x).Eq. (4.4) is interesting because it shows

Gerber and Shiu’s discounted penalty function revisited

Gerber and Shiu (1998) introduced the function Φ0,α(u)=E(w(U(T0),|U(T0)|)e−αT0I(T0<∞)),where T0 is as defined in Example 4.1. Through this function we can study the joint distribution of surplus prior to ruin, the deficit at ruin and the time of ruin. They defined the following ruin function: Ψα(u)=E(e−αT0+ρU(T0)I(T0<∞)),where ρ is the unique non-negative root of Lundberg’s fundamental equation for the classical risk model, i.e. −α+cξ+λ0e−ξxf(x)dx−1=0.They showed that Φ0,α(u) and Ψα(u)

Concluding remarks

We have derived the following: an integral equation for Φδ,α(u); the Laplace transform of an auxiliary function of Φδ(u); an exact expression for Φδ(0); relationships between ruin functions and the ultimate ruin probability. We have also generalised Dickson’s (1992) formulae from the case when δ=0 to the case when δ>0. Ruin functions are very complicated when δ>0. Although we have discussed some properties of ruin functions when δ>0 we have been unable to find many explicit results. Further

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